ight)^2 $ term has same denominator $ rac{64}{9} $, and $ y^2 $ has $ rac{192}{9} $, so it's **elliptical** in $ x/z $-plane. But more precisely, since the equation resembles $ rac{x^2 + y^2}{a^2} + rac{(z - z_0)^2}{b^2} = 1 $, with $ a

Sat, 09 May 2026 05:05:05 +0000

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