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\( -4.9t^2 + 20t + 50 = 0 \).
Solve using the quadratic formula: \( t = rac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = -4.9 \), \( b = 20 \), \( c = 50 \).
The discriminant \( \Delta = 20^2 - 4(-4.9)(50) = 400 + 980 = 1380 \).

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